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​LETS COMPARE ANSWERS~ Limits Homework Sheet From February 25th: Question || Answer || x^2+x/x+1... Sub in -1 for x and you get 2/0 which is no limit. || could it be 2x ? ||
 * Part B
 * 5a) || 2 ||
 * b) || Root of 2 ||
 * 6) || Just sub 1 in. ||
 * 7a) || 4 ||
 * b) || 1 ||
 * c) || 27 ||
 * d) || -1/4 ||
 * e) || 1/4 ||
 * f) || ?? ||
 * 8a) || 1/12 ||
 * b) || 9 - how did you get this? can you post your answer? ||
 * c) || 1/5 ||
 * d) || 1/2 (check out [] for solution) ||
 * e) || 1/12 ||
 * f) || 1/12 ||
 * 9a) || 0 ||
 * b) || 0 ||
 * c) || no limit - i got -1
 * d) || multiply the top by itself but use +1... the answer is -1/2
 * i got 1/2, and the LDoes Exist
 * I got 1/2 as well. (I made a mistake for saying no limit.) ||
 * e) || ???
 * f) || 0 -could you post the solution please? ||
 * 10a) || the limit does not exist ||
 * b) || " ||
 * c) || " ||
 * d) || " ||

did anybody figure out how to do #14-15?
We don't have to know those. He said to ignore them, didn't he? Investigate Indeterminate Form Sheet From February 26th:


 * Question || Answer ||
 * 1. || 2 ||
 * 2. || No limit ||
 * 3. || 4 ||
 * 4. || m/n...?maybe? ||
 * 5. || No limit ||
 * 6. || 3 ||

why is there no limit for #2 - if you divide by zero that doesn't necessarily mean no limit?
yea why does #2 have no llimit and also #5 - it is actually 0/0, then why does the lim not exist? - hasha If you divide by zero, that means there is a vertical asymptote and when there is a vertical asymptote, it either goes to +/- infinity, so essentially there is no limit.

What were the steps in getting the answer to 6? I multiplied by the conjugate, but then I get stuck. Can someone post their sol'n or explain please?-Simone
did anyone get 3 for number 6?... i m not sure what i did though- Qing so i divided root x from the top and i have x^1\2(x^3/2-1)/(x^1/2-1) using the formula found in 4, i got to x^1/2(3) which is 3 because x is one. um yeahhhhhh lol

I also got 3 for #6. I said let x^1/2= a. and then eventually you factor it out to a(a^2 + a + 1) // -Nan //